How many grams of N₂ are required to react with 2.30 moles of Mg in the following process?
3 Mg + N₂ → Mg₃N₂? (Mg = 24.3 g/mol,N = 14.0 g/mol)

Question

How many grams of N₂ are required to react with 2.30 moles of Mg in the following process? 3 Mg + N₂ → Mg₃N₂? (Mg = 24.3 g/mol,N = 14.0 g/mol) A)21.5 g B)0.767 g C)64.4 g D)0.027 g E)193.2 g

Quizplus · Accepted Answer

The balanced chemical equation is:3 Mg + N₂ → Mg₃N₂From the equation, we can see that 3 moles of Mg react with 1 mole of N₂. Therefore, 2.30 moles of Mg will react with 2.30/3 = 0.767 moles of N₂. The molar mass of N₂ is 28.0 g/mol, so the mass of N₂ required is 0.767 moles * 28.0 g/mol = 21.5 g.

How Many Grams of N2 Are Required to React with 2.30

How Many Grams of N₂ Are Required to React with 2.30