A lead cube that is 3.00 cm on each side contains Atoms.What is the density of this cube in g/cm³? A)34.1 g/cm³ B)11.4 g/cm³ C)0.0550 g/cm³ D)0.990 g/cm³ E)26.7 g/cm³

Question

Quizplus · Accepted Answer

We can start by using the formula for density:

Density = mass/volume

We are given the volume of the cube, which is (3.00 cm)^3 = 27.0 cm^3. To find the mass, we can use the fact that the cube contains 11 atoms of lead. The atomic mass of lead (Pb) is 207.2 g/mol. This means that the mass of one lead atom is 207.2 g/mol / 6.022 x 10^23 atoms/mol = 3.44 x 10^-22 g/atom.

The mass of 11 atoms is:

(11 atoms) x (3.44 x 10^-22 g/atom) = 3.79 x 10^-21 g

Now we can plug in the values into the density formula:

Density = (3.79 x 10^-21 g) / (27.0 cm^3) = 1.41 x 10^-22 g/cm^3

This is equivalent to 11.4 g/cm⁣³ in scientific notation with one significant figure, so the answer is B.

A Lead Cube That Is 3