How many atoms of silicon are contained in 8.50 × 10^-5 grams? A)1.44 × 10²³ atoms B)1.82 × 10¹⁸ atoms C)5.02 × 10³⁰ atoms D)5.02 × 10¹⁸ atoms E)1.82 × 10²⁰ atoms

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Quizplus · Accepted Answer

To find the number of silicon atoms in 8.50 × 10^-5 grams, we use Avogadro's number (6.022 × 10^23 atoms/mol) and the molar mass of silicon (approximately 28.09 g/mol). First, convert the mass of silicon to moles: $ \frac{8.50 \times 10^{-5} \text{ grams}}{28.09 \text{ g/mol}} $. This gives approximately $3.03 \times 10^{-6}$ moles of silicon. Then, multiply the moles by Avogadro's number to find the number of atoms: $3.03 \times 10^{-6} \text{ moles} \times 6.022 \times 10^{23} \text{ atoms/mol} = 1.82 \times 10^{18} \text{ atoms}$.

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