31.0 grams of the element phosphorus contain: A)6.02 × 10²³ P₄ molecules B)31.0 × (6.02 × 10²³)P atoms C)6.02 × 10²³ P atoms D)31.0 P atoms E)31.0 moles of P

Question

Quizplus · Accepted Answer

One mole of any element contains Avogadro's number (6.02 × 10^23) atoms or molecules. Therefore, 31.0 grams of phosphorus will contain the same number of atoms as 6.02 × 10^23 P atoms, which is option C. The other options either have incorrect calculations or are not a measure of the number of atoms present.

31.0 Grams of the Element Phosphorus Contain