An FM radio tuning circuit has a coil with an inductance of 0.0021 mH.What is the value of the capacitance if the set is tuned to 102.7 MHz? A) 4.6 × 10−⁶ μF B) 3.6 × 10−⁶ μF C) 7.4 × 10−⁶ μF D) 1.14 × 10−⁶ μF E) 11.3 × 10−⁶ μF

Question

Quizplus · Accepted Answer

The formula for capacitance in an FM radio tuning circuit is:

C = 1 / (2πf L)

Where:
C = capacitance in farads
f = frequency in hertz
L = inductance in henries
π = 3.1416

First, we need to convert the frequency to hertz:

102.7 MHz = 102.7 x 10^6 Hz

Now we can plug in the values and solve for capacitance:

C = 1 / (2π x 102.7 x 10^6 x 0.0021 x 10^-3)
C = 1.14 x 10^-16 F
C = 1.14 x 10^-7 µF
C = 0.114 µF

Therefore, the answer is D, 1.14 x 10^-7 µF.

An FM Radio Tuning Circuit Has a Coil with an Inductance