What is the average power dissipation in an RLC series circuit in which R = 140 Ω,L = 0.38 H,and C = 10 µF driven at resonance by a 102-V (rms)source?
A) 70 W
B) 9 W
C) 15 W
D) 26 W
E) 92 W

Question

What is the average power dissipation in an RLC series circuit in which R = 140 Ω,L = 0.38 H,and C = 10 µF driven at resonance by a 102-V (rms)source?
A) 70 W
B) 9 W
C) 15 W
D) 26 W
E) ​92 W

Quizplus · Accepted Answer

At resonance, the impedance of the circuit is purely resistive, so the average power dissipation is given by P = V^2/R, where V is the rms voltage. Thus, P = (102^2)/140 = 74.29 W, which rounds to 70 W.

What Is the Average Power Dissipation in an RLC Series