A uniform 4.5-T magnetic field passes through the plane of a wire loop 0.20 m² in area.What flux passes through the loop when the direction of the 4.5-T field is at a 30° angle to the normal of the loop plane? A) 0.39 T⋅m² B) 5.0 T⋅m² C) 0.78 T⋅m² D) 0.225 T⋅m²

Question

Quizplus · Accepted Answer

The flux passing through the wire loop can be calculated using the formula:

Φ = B*A*cos(θ)

where Φ is the flux, B is the magnetic field strength, A is the area of the loop, and θ is the angle between the magnetic field and the normal to the loop.

In this case, B = 4.5 T, A = 0.20 m^2, and θ = 30°. Using the above formula, we get:

Φ = 4.5 T * 0.20 m^2 * cos(30°) = 0.78 T⋅m^2

Therefore, the answer is (C) 0.78 T⋅m^2.

A Uniform 4