Electrons in a particle beam each have a kinetic energy of 3.2 × 10−¹⁷ J.What is the magnitude of the electric field that will stop these electrons in a distance of 0.05 m? (e = 1.6 × 10−¹⁹ C) A) 2000 N/C B) 4000 N/C C) 200 N/C D) 1000 N/C

Question

Quizplus · Accepted Answer

The equation to calculate the electric field is:

E = (2KE)/qD^2

where KE is the kinetic energy of each electron, q is the charge of each electron, and D is the distance over which the electrons need to be stopped.

Plugging in the given values, we get:

E = (2*3.2*10^-19 J)/(1.6*10^-19 C*0.05 m^2)
E = 4000 N/C

Therefore, the magnitude of the electric field required to stop these electrons in 0.05 m distance is 4000 N/C, which corresponds to choice B.

Electrons in a Particle Beam Each Have a Kinetic Energy