A parallel-plate capacitor has a capacitance of 24 µF.What potential difference across the plates is required to store 6.8 × 10−⁴ C on this capacitor? A) 28.3 V B) 28.3 × 10^-2 V C) 39.2 × 10−⁸ V D) 32.6 V E) 32.6× 10−⁸ V

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Quizplus · Accepted Answer

The potential difference (V) can be calculated using the formula Q = CV, where Q is the charge and C is the capacitance. Rearranging gives V = Q/C. Substituting the given values, V = (6.8 × 10^-4 C) / (24 × 10^-6 F) = 28.3 V.

A Parallel-Plate Capacitor Has a Capacitance of 24 µF