If a doubly-ionized oxygen atom (O^-2)is accelerated from rest by going through a potential difference of 21 V,what will be the change in its kinetic energy? A) 10 eV B) 21 eV C) 42 eV D) 33 eV E) none of the above

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Quizplus · Accepted Answer

The change in kinetic energy of a charged particle is equal to the charge of the particle multiplied by the potential difference. A doubly-ionized oxygen atom has a charge of -2e, so the change in kinetic energy is 2e * 21 V = 42 eV.

If a Doubly-Ionized Oxygen Atom (O-2)is Accelerated from Rest by Going

If a Doubly-Ionized Oxygen Atom (O^-2)is Accelerated from Rest by Going