A majorette takes two batons and fastens them together in the middle at right angles to make an "x" shape.Each baton was 0.60 m long and each ball on the end is 0.10 kg.(Ignore the mass of the rods. )What is the moment of inertia if the arrangement is spun around an axis formed by one of the batons? A) 0.018 kg·m² B) 0.036 kg·m² C) 0.06 kg·m² D) 0.12 kg·m² E) 0.054 kg·m²

Question

Quizplus · Accepted Answer

The moment of inertia of a rod about an axis through its center perpendicular to the rod is (1/12)ML^2. The moment of inertia of a point mass about an axis is mr^2. The moment of inertia of the arrangement about an axis formed by one of the batons is:I = (1/12)(0.10 kg)(0.60 m)^2 + (0.10 kg)(0.60 m)^2 + (0.10 kg)(0.60 m)^2 = 0.018 kg·m^2

A Majorette Takes Two Batons and Fastens Them Together in the Middle