A horizontal force of 950 N is needed to overcome the force of static friction between a level floor and a 150-kg crate.If g = 9.8 m/s²,what is the coefficient of static friction? A) 64.63 B) 6.46 C) 1.55 D) 0.65 E) 6.33

Question

Quizplus · Accepted Answer

We know that the force of static friction (f_s) is given by f_s = u_s N, where u_s is the coefficient of static friction and N is the normal force (equal to the weight of the object in this case). Since the crate is on a level floor, the normal force is equal to the weight of the crate, which is m*g, where m is the mass of the crate and g is the acceleration due to gravity. 
Thus, we have f_s = u_s*m*g.
We are told that a horizontal force of 950 N is needed to overcome the force of static friction between the crate and the floor. This means that f_s = 950 N. 
Substituting in the values we know, we get:
950 N = u_s*150 kg*9.8 m/s^2
Solving for u_s gives:
u_s = 0.65
Therefore, the coefficient of static friction is 0.65, which is answer choice D.

A Horizontal Force of 950 N Is Needed to Overcome