A baseball thrown from the outfield is released from shoulder height at an initial velocity of 29.1 m/s at an initial angle of 45° with respect to the horizontal.What is the maximum vertical displacement that the ball reaches during its trajectory?

A) 21.6 m
B) 43.2 m
C) 64.8 m
D) 43.2 m.
E) 86.4 m

Question

A baseball thrown from the outfield is released from shoulder height at an initial velocity of 29.1 m/s at an initial angle of 45° with respect to the horizontal.What is the maximum vertical displacement that the ball reaches during its trajectory?
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A) 21.6 m
B) 43.2 m
C) 64.8 m
D) 43.2 m.
E) 86.4 m

Quizplus · Accepted Answer

The maximum vertical displacement can be calculated using the formula: $ h = \frac{v^2 \sin^2(\theta)}{2g} $, where $ v = 29.1 \, \text{m/s} $, $ \theta = 45^\circ $, and $ g = 9.8 \, \text{m/s}^2 $. Plugging in the values, $ h = \frac{(29.1)^2 \times (\sin(45^\circ))^2}{2 \times 9.8} \approx 21.6 \, \text{m} $.

A Baseball Thrown from the Outfield Is Released from Shoulder