A taxicab moves five blocks due north,six blocks due east,and another three blocks due north.Assume all blocks are of equal size.What is the magnitude of the taxi's displacement,start to finish?

A) 14 blocks
B) 6.7 blocks
C) 7.8 blocks
D) 10 blocks
E) 8 blocks

Question

A taxicab moves five blocks due north,six blocks due east,and another three blocks due north.Assume all blocks are of equal size.What is the magnitude of the taxi's displacement,start to finish?
​
A) 14 blocks
B) 6.7 blocks
C) 7.8 blocks
D) 10 blocks
E) 8​ blocks

Quizplus · Accepted Answer

The taxi's total displacement is the straight-line distance from the starting point to the ending point. It moves a total of 8 blocks north (5 + 3) and 6 blocks east. Using the Pythagorean theorem, the displacement is √(8² + 6²) = √(64 + 36) = √100 = 10 blocks.

A Taxicab Moves Five Blocks Due North,six Blocks Due East,and