A rock is rolled in the sand.It starts at 5.0 m/s,moves in a straight line for a distance of 6.0 m,and then stops.What is the magnitude of the average acceleration? A)2.1 m/s² B)4.2 m/s² C)5.4 m/s² D)6.2 m/s²

Question

Quizplus · Accepted Answer

The magnitude of the average acceleration can be calculated using the formula $a = \frac{v^2 - u^2}{2s}$, where $v$ is the final velocity (0 m/s, since it stops), $u$ is the initial velocity (5.0 m/s), and $s$ is the distance (6.0 m). Plugging in the values, we get $a = \frac{0^2 - 5.0^2}{2 \times 6.0} = \frac{-25}{12} = -2.1$ m/s$^2$. The negative sign indicates the direction of acceleration is opposite to the direction of motion, but since the question asks for magnitude, we take the absolute value, which is 2.1 m/s$^2$.

A Rock Is Rolled in the Sand