A rock is thrown straight up with an initial velocity of 24.9 m/s.What maximum height will the rock reach before starting to fall downward? (Take acceleration due to gravity as 9.80 m/s². )

Question

Quizplus · Accepted Answer

The maximum height can be calculated using the formula: $ h = \frac{v^2}{2g} $, where $ v = 24.9 \, \text{m/s} $ and $ g = 9.8 \, \text{m/s}^2 $. Plugging in the values, $ h = \frac{(24.9)^2}{2 \times 9.8} = 31.6 \, \text{m} $.

A Rock Is Thrown Straight Up with an Initial Velocity