A vehicle designed to operate on a drag strip accelerates from zero to 28 m/s while undergoing a straight line path displacement of 48 m.What is the vehicle's acceleration if its value may be assumed to be constant?

Question

Quizplus · Accepted Answer

We can use the following formula to calculate acceleration:

a = (v_f - v_i)/t

Where v_f is the final velocity, v_i is the initial velocity (which is zero in this case), and t is the time taken to reach the final velocity. We can use the following formula to calculate the time taken:

d = (v_f + v_i)/2 * t

Where d is the displacement (which is 48 m in this case). Rearranging this formula to solve for t, we get:

t = d/(v_f + v_i)/2

Substituting the given values, we get:

t = 48/(28 + 0)/2 = 48/14 = 3.43 s (rounded to two decimal places)

Now, we can substitute the values of v_f, v_i, and t into the first formula to calculate the acceleration:

a = (v_f - v_i)/t = (28 - 0)/3.43 = 8.16 m/s^2 (rounded to two decimal places)

Therefore, the best choice is C, 8 m/s^2.

A Vehicle Designed to Operate on a Drag Strip Accelerates