A 3.140 molal solution of NaCl is prepared.How many grams of NaCl are present in a sample containing 2.692 kg of water?
A)299.7 g
B)494.0 g
C)144.6 g
D)845.3 g
E)none of these

Question

Quizplus · Accepted Answer

Firstly, we need to calculate the moles of NaCl present in a kilogram of water:

3.140 mol of NaCl is present in 1 kg of water

Therefore, 3.140/1000 mol of NaCl is present in 1 gram of water

Now we can calculate the total moles of NaCl in the 2.692 kg of water:

3.140/1000 x 2.692 kg = 0.0084596 mol

Finally, we can convert this to grams of NaCl:

0.0084596 mol x 58.44 g/mol = 0.494 g

Therefore, the answer is B) 494.0 g.

A 3140 Molal Solution of NaCl Is Prepared