In the Lewis dot formula that minimizes formal charge,how many bonds are there in the tetrathionate ion,S₄O₆^2- ? A)7 B)9 C)15 D)11 E)13

Question

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The tetrathionate ion, with the formula $S_4O_6^{2-}$, consists of a chain of four sulfur atoms with two oxygen atoms double-bonded to two of the sulfur atoms. To minimize formal charges and satisfy the octet rule, the structure involves two central sulfur atoms each double-bonded to an oxygen atom and single-bonded to another sulfur atom, with the two terminal sulfur atoms each forming two single bonds with the central sulfur atoms and carrying a negative charge. This results in a total of 13 bonds: 4 S-S single bonds, 2 S=O double bonds (counting as 4 bonds), and 5 S-O single bonds.

In the Lewis Dot Formula That Minimizes Formal Charge,how Many