Consider the fermentation reaction of glucose:
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
A 1) 00-mol sample of C₆H₁₂O₆ was placed in a vat with 100 g of yeast.If 67.7 g of C₂H₅OH was obtained,what was the percent yield of C₂H₅OH?

Question

Quizplus · Accepted Answer

The percent yield is calculated by dividing the actual yield by the theoretical yield and multiplying by 100%. The theoretical yield is the amount of product that would be obtained if the reaction went to completion. In this case, the theoretical yield of C2H5OH is 92.1 g. The actual yield is 67.7 g. Therefore, the percent yield is (67.7 g / 92.1 g) x 100% = 73.5%.

Consider the Fermentation Reaction of Glucose