Complete combustion of a 0.40-mol sample of a hydrocarbon,C_xH_y,gives 2.40 mol of CO₂ and 1.60 mol of H₂O.The molecular formula of the original hydrocarbon is A)C₂H₈. B)C₆H₈. C)C₉H₁₆. D)C₅H₅. E)C₄H₇.

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The Answer of Complete combustion of a 0.40-mol sample of a hydrocarbon,C_xH_y,gives 2.40 mol of CO₂ and 1.60 mol of H₂O.The molecular formula of the original hydrocarbon is A)C₂H₈. B)C₆H₈. C)C₉H₁₆. D)C₅H₅. E)C₄H₇.

Complete Combustion of a 0