The analysis of an organic compound showed that it contained 0.105 mol of C,0.315 mol of H,and 0.0350 mol of N.Its molecular mass is 59 amu.How many atoms of carbon are there in the empirical formula for the compound,and how many are in the molecular formula?
A)empirical = 2,molecular = 3
B)empirical = 3,molecular = 9
C)empirical = 3,molecular = 3
D)empirical = 2,molecular = 4
E)empirical = 5,molecular = 10

Question

Quizplus · Accepted Answer

To find the empirical formula, divide the moles of each element by the smallest number of moles: C (0.105/0.0350 = 3), H (0.315/0.0350 = 9), N (0.0350/0.0350 = 1), giving CH3N. The empirical formula mass is approximately 59 amu, matching the molecular mass, so the molecular formula is the same as the empirical formula, with 3 carbon atoms.

The Analysis of an Organic Compound Showed That It Contained