The total number of oxygen atoms in 1.93 g of CaCO₃ (MM = 100.0 g/mol)is A)2.24 × 10²³. B)4.65 × 10²². C)3.49 × 10²². D)1.92 × 10²³. E)5.81 × 10²².

Question

Quizplus · Accepted Answer

First, we need to calculate the number of moles of CaCO₃: moles CaCO₃ = mass / MM moles CaCO₃ = 1.93 g / 100.0 g/mol moles CaCO₃ = 0.0193 mol Next, we need to use the subscripts in the formula of CaCO₃ to determine the number of oxygen atoms: number of oxygen atoms = 3 x moles CaCO₃ number of oxygen atoms = 3 x 0.0193 mol number of oxygen atoms = 0.0579 mol Finally, we can use Avogadro's number to convert the number of oxygen atoms to a more convenient unit: number of oxygen atoms = 0.0579 mol x 6.022 x 10^23 atoms/mol number of oxygen atoms = 3.49 x 10^22 Therefore, the total number of oxygen atoms in 1.93 g of CaCO₃ is 3.49 x 10^22, which corresponds to answer choice C.

The Total Number of Oxygen Atoms in 1