How many atoms are present in 495 g of KPF₆ (MM = 184.1 g/mol)? A)2.38 × 10²⁵ B)1.62 × 10²¹ C)2.69 × 10²¹ D)1.21 × 10²⁶ E)1.29 × 10²⁵

Question

Quizplus · Accepted Answer

First, calculate the moles of KPF₆: 495 g / 184.1 g/mol = 2.69 mol. Each molecule of KPF₆ contains 8 atoms (1 K, 1 P, 6 F). Therefore, the total number of atoms is 2.69 mol × 6.022 × 10²³ molecules/mol × 8 atoms/molecule = 1.29 × 10²⁵ atoms.

How Many Atoms Are Present in 495 G of KPF6

How Many Atoms Are Present in 495 G of KPF₆