In a particular mass of KAu(CN)₂,there are 6.66 × 10²⁰ atoms of gold.What is the total number of atoms in this sample? A)1.33 × 10²¹ B)2.00 × 10²¹ C)4.00 × 10²¹ D)3.33 × 10²¹ E)2.66 × 10²¹

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To find the total number of atoms, we need to add up the atoms of each element present in the compound. The compound KAu(CN)₂ contains: - 1 atom of potassium (K) - 1 atom of gold (Au) - 2 atoms of carbon (C) - 2 atoms of nitrogen (N) - 2 atoms of sulfur (S) - 12 atoms of hydrogen (H) - 12 atoms of cyanide (CN) Since we are given that there are 6.66 × 10²⁰ atoms of gold, we know that the total number of atoms in the compound is: 6.66 × 10²⁰ atoms of gold / (1 atom of gold/1 molecule of KAu(CN)₂) = 6.66 × 10²⁰ molecules of KAu(CN)₂ To find the total number of atoms, we can multiply the number of molecules by the total number of atoms in each molecule: 6.66 × 10²⁰ molecules of KAu(CN)₂ x 23 atoms per molecule = 1.53 × 10²² atoms Therefore, the best choice is C: 4.00 × 10²¹.

In a Particular Mass of KAu(CN)2,there Are 6

In a Particular Mass of KAu(CN)₂,there Are 6