Which combination of protons,neutrons,and electrons correctly represents a ⁵⁷Fe nuclide? A)26 protons,31 neutrons,57 electrons B)26 protons,31 neutrons,31 electrons C)26 protons,31 neutrons,26 electrons D)57 protons,26 neutrons,57 electrons E)57 protons,26 neutrons,26 electrons

Question

Quizplus · Accepted Answer

The atomic number (number of protons) of the nuclide is given by the subscript before the chemical symbol, which is 26 (⁵⁷Fe). The mass number (number of protons and neutrons) is given by the superscript after the chemical symbol, which is 57. Therefore, the number of neutrons is 57 - 26 = 31. The number of electrons in a neutral atom is equal to the number of protons, so there are also 26 electrons. The only choice that matches these numbers is C.

Which Combination of Protons,neutrons,and Electrons Correctly Represents a 57Fe Nuclide

Which Combination of Protons,neutrons,and Electrons Correctly Represents a ⁵⁷Fe Nuclide