Calculate the molar solubility of thallium(I)chloride in 0.40 M NaCl at 25°C.K_sp for TlCl is 1)7 × 10^-4. A)6)8 × 10^-5 M B)4)2 × 10^{- 4} M C)8)2 × 10^-3 M D)1)3 × 10^-2 M

Question

Quizplus · Accepted Answer

The solubility of TlCl in pure water at 25°C is given by:
Ks = [Tl+][Cl-] = 7 × 10^-4

In the presence of NaCl, the ionic activity product of TlCl must be equal to or less than Ks in order to remain saturated. Therefore, the new solubility of TlCl in the presence of 0.40 M NaCl can be calculated using the common ion effect:

Ks = [Tl+][Cl-] = (x)(0.40 + x)

where x is the molar solubility of TlCl in 0.40 M NaCl.

Solving for x, we obtain:

x = 4.2 × 10^-4 M

Therefore, the molar solubility of TlCl in 0.40 M NaCl at 25°C is 4.2 × 10^-4 M or Choice (B).

Calculate the Molar Solubility of Thallium(I)chloride in 0