What is the mole fraction of I₂ in a solution made by dissolving 27.8 g of I₂ in 245 g of hexane,C₆H₁₄? A)0)0371 B)0)0385 C)0)0715 D)0)0770

Question

Quizplus · Accepted Answer

The mole fraction of I2 is calculated as follows:Mole fraction of I2 = moles of I2 / (moles of I2 + moles of hexane)Moles of I2 = 27.8 g / 253.8 g/mol = 0.11 molMoles of hexane = 245 g / 86.18 g/mol = 2.84 molMole fraction of I2 = 0.11 mol / (0.11 mol + 2.84 mol) = 0.0371Therefore, the mole fraction of I2 in the solution is 0.0371.

What Is the Mole Fraction of I2 in a Solution

What Is the Mole Fraction of I₂ in a Solution