Methane and oxygen react to form carbon dioxide and water.What mass of water is formed if 0.80 g of methane reacts with 3.2 g of oxygen to produce 2.2 g of carbon dioxide?
A)1)8 g
B)2)2 g
C)3)7 g
D)4)0 g

Question

Quizplus · Accepted Answer

The balanced chemical equation for the reaction is:CH4 + 2O2 -> CO2 + 2H2OFrom the equation, we can see that 1 mole of methane reacts with 2 moles of oxygen to produce 1 mole of carbon dioxide and 2 moles of water.The molar mass of methane is 16 g/mol, and the molar mass of water is 18 g/mol.Therefore, 0.80 g of methane is equal to 0.80 g / 16 g/mol = 0.05 mol of methane.3.2 g of oxygen is equal to 3.2 g / 32 g/mol = 0.1 mol of oxygen.According to the balanced chemical equation, 0.05 mol of methane reacts with 0.1 mol of oxygen to produce 0.05 mol of carbon dioxide and 0.1 mol of water.Therefore, the mass of water formed is 0.1 mol * 18 g/mol = 1.8 g.

Methane and Oxygen React to Form Carbon Dioxide and Water