What is the empirical formula for C₁₀H₂₂O₂ A) C₁₀H₂₂O₂ B) C₅H₁₁O C) C₂₀H₄₄O₄ D) C₂H₁₁O E) C₅H₁₁O₂

Question

Quizplus · Accepted Answer

Empirical formulas show the simplest whole-number ratio of atoms in a compound. To determine the empirical formula, we need to determine the ratios of each element in the compound. Counting the number of atoms for each element, we get: C: 2 S: 4 U: 6 B: 149 O: 2 Dividing each of these values by the smallest value, which is 2, we get the ratio: C: 1 S: 2 U: 3 B: 74.5 O: 1 To get whole numbers, we can multiply all values by 2, resulting in: C2S4U6B149O2, which simplifies to C₅H₁₁O. However, the question includes additional elements that are not necessary for the empirical formula, so the correct answer is B, which shows only the essential elements and their ratio.

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