Hydrogen chloride gas can be prepared by the following reaction: 2NaCl(s) + H₂SO₄(aq) $\rarr$ 2HCl(g) + Na₂SO₄(s)
How many grams of HCl can be prepared from 2.00 mol H₂SO₄ and 2.56 mol NaCl

Question

Hydrogen chloride gas can be prepared by the following reaction: 2NaCl(s) + H₂SO₄(aq)

\rarr

2HCl(g) + Na₂SO₄(s)
How many grams of HCl can be prepared from 2.00 mol H₂SO₄ and 2.56 mol NaCl

Quizplus · Accepted Answer

The balanced chemical equation shows that 2 moles of NaCl react with 1 mole of $H_2SO_4$ to produce 2 moles of HCl. Given 2.00 mol of $H_2SO_4$ and 2.56 mol of NaCl, NaCl is the limiting reagent. Thus, 2.56 mol of NaCl will produce 2.56 mol of HCl (since the ratio is 1:1 from NaCl to HCl in the reaction). The molar mass of HCl is approximately 36.5 g/mol, so 2.56 mol * 36.5 g/mol = 93.44 g, which rounds to 93.3 g.

Hydrogen Chloride Gas Can Be Prepared by the Following Reaction →\rarr→

Hydrogen Chloride Gas Can Be Prepared by the Following Reaction $\rarr$