The following net ionic equation correctly shows the result of this experiment: A piece of lead metal was added to an aqueous solution of copper(II) nitrate, and within a few minutes it was observed that the lead turned black and crumbled. The characteristic blue solution of copper(II) ions had faded. (NOTE: Lead forms a 2+ ion when it reacts.)
Pb(s) + Cu²⁺(aq) $\rarr$ Pb²⁺(aq) + Cu(s)

Question

The following net ionic equation correctly shows the result of this experiment: A piece of lead metal was added to an aqueous solution of copper(II) nitrate, and within a few minutes it was observed that the lead turned black and crumbled. The characteristic blue solution of copper(II) ions had faded. (NOTE: Lead forms a 2+ ion when it reacts.)
Pb(s) + Cu²⁺(aq)

\rarr

Pb²⁺(aq) + Cu(s)

Quizplus · Accepted Answer

The net ionic equation correctly represents the reaction between lead metal and copper(II) nitrate, which forms lead sulfide and copper metal. The observed black color and crumbling of the lead is due to the formation of insoluble lead sulfide. The fading of the blue color of copper(II) ions indicates that copper has been reduced to its elemental form.

The Following Net Ionic Equation Correctly Shows the Result of This