If 145 grams of potassium nitrate were added to water to make 1,500 mL of solution. What would the molarity of the resulting solution be
A) 0.956 M
B) 0.856 M
C) 0.756 M
D) 0.656 M
E) None of the above

Question

Quizplus · Accepted Answer

The molarity (M) of a solution is calculated using the formula M = moles of solute / liters of solution. Potassium nitrate (KNO3) has a molar mass of approximately 101.1 g/mol. Therefore, 145 grams of KNO3 is equivalent to 145 g / 101.1 g/mol = 1.434 moles. The volume of the solution is 1,500 mL, which is 1.5 liters. Thus, the molarity of the solution is 1.434 moles / 1.5 L = 0.956 M.

If 145 Grams of Potassium Nitrate Were Added to Water