A 20.00 mL sample of 0.1015 M nitric acid is introduced into a flask, and water is added until the volume of the solution reaches 250. mL. What is the concentration of nitric acid in the final solution A) 1.27 M B) 8.12 * 10^-3 M C) 0.406 M D) 3.25 * 10^-2 M E) 5.08 * 10^-4 M

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Quizplus · Accepted Answer

The concentration is calculated using the dilution formula: C1V1 = C2V2. Here, C1 = 0.1015 M, V1 = 20.00 mL, V2 = 250.00 mL. Solving for C2 gives 8.12 * 10^-3 M.

A 2000 ML Sample of 0