How many liters of chlorine gas at 25^$\circ$C and 0.950 atm can be produced by the reaction of 12.0 g of MnO₂ with excess HCl(aq) according to the following chemical equation
MnO₂(s) + 4HCl(aq) $\rarr$ MnCl₂(aq) + 2H₂O(l) + Cl₂(g)

Question

How many liters of chlorine gas at 25^$\circ$C and 0.950 atm can be produced by the reaction of 12.0 g of MnO₂ with excess HCl(aq) according to the following chemical equation
MnO₂(s) + 4HCl(aq)

\rarr

MnCl₂(aq) + 2H₂O(l) + Cl₂(g)

Quizplus · Accepted Answer

The Answer of How many liters of chlorine gas at 25^$\circ$C and 0.950 atm can be produced by the reaction of 12.0 g of MnO₂ with excess HCl(aq) according to the following chemical equation MnO₂(s) + 4HCl(aq) $\rarr$MnCl₂(aq) + 2H₂O(l) + Cl₂(g) A) 5.36 * 10^-3 L B) 0.138 L C) 0.282 L D) 3.09 L E) 3.55 L

How Many Liters of Chlorine Gas at 25 ∘\circ∘ C and 0

How Many Liters of Chlorine Gas at 25^$\circ$C and 0