Calculate the density, in g/L, of SF₆ gas at 27^$\circ$C and 0.500 atm pressure. A) 3.38 * 10^-3 g/L B) 2.96 g/L C) 22.4 g/L D) 32.9 g/L E) 3.38 kg/L

Question

Quizplus · Accepted Answer

To calculate the density of SF6 gas, use the ideal gas law: PV = nRT. First, convert the temperature to Kelvin (27°C + 273 = 300 K). The molar mass of SF6 is 146.06 g/mol. Using the ideal gas law, rearrange to find density (d = PM/RT). Substitute P = 0.500 atm, M = 146.06 g/mol, R = 0.0821 L·atm/mol·K, and T = 300 K to find the density: d = (0.500 * 146.06) / (0.0821 * 300) = 2.96 g/L.

Calculate the Density, in G/L, of SF6 Gas at 27 ∘\circ∘

Calculate the Density, in G/L, of SF₆ Gas at 27^$\circ$