The heat of solution of KCl is 17.2 kJ/mol and the lattice energy of KCl(s) is 701.2 kJ/mol. Calculate the total heat of hydration of 1.00 mol of gas phase K⁺ ions and Cl^- ions. A) -718 kJ B) -684 kJ C) 684 kJ D) 718 kJ E) None of these.

Question

Quizplus · Accepted Answer

The heat of solution is the sum of the lattice energy and the heat of hydration. Therefore, the heat of hydration = heat of solution - lattice energy = 17.2 kJ/mol - 701.2 kJ/mol = -684 kJ/mol.

The Heat of Solution of KCl Is 17