Calculate the Standard Enthalpy of Formation of Liquid Methanol, CH₃OH(l)

Calculate the standard enthalpy of formation of liquid methanol, CH₃OH(l) , using the following information: $\begin{array}{ll}\mathrm{C} \text { (graph) }+\mathrm{O}_{2} \rightarrow \mathrm{CO}_{2}(\mathrm{g}) & \Delta \mathrm{H}^{\circ}=-393.5 \mathrm{~kJ} / \mathrm{mol} \\\mathrm{H}_{2}(\mathrm{g}) +(1 / 2) \mathrm{O}_{2} \rightarrow \mathrm{H}_{2} \mathrm{O}(\mathrm{l}) & \Delta \mathrm{H}^{\circ}=-285.8 \mathrm{~kJ} / \mathrm{mol} \\\mathrm{CH}_{3} \mathrm{OH}(\mathrm{l}) +(3 / 2) \mathrm{O}_{2}(\mathrm{g}) \rightarrow \mathrm{CO}_{2}(\mathrm{~g}) +2 \mathrm{H}_{2} \mathrm{O}(\mathrm{l}) & \Delta \mathrm{H}^{\circ}=-726.4 \mathrm{~kJ} / \mathrm{mol}\end{array}$

A) -1,691.5 kJ/mol
B) -238.7 kJ/mol
C) -47.1 kJ/mol
D) 47.1 kJ/mol
E) 1691.5 kJ/mol