What is the osmotic pressure of a 0.25 M solution of sucrose at 37^$\circ$C (R = 0.0821 L·atm/K·mol) A) 6.6 * 10^-5 atm B) 0.76 atm C) 6.4 atm D) 100 atm E) 940 atm

Question

Quizplus · Accepted Answer

The osmotic pressure (π) can be calculated using the formula π = iMRT. For sucrose, i = 1 (since it does not dissociate), M = 0.25 M, R = 0.0821 L·atm/K·mol, and T = 310 K (37°C + 273). Substituting these values gives π = 1 * 0.25 * 0.0821 * 310 = 6.4 atm.

What Is the Osmotic Pressure of a 0 ∘\circ∘ C (R = 0

What Is the Osmotic Pressure of a 0 $\circ$ C (R = 0