What is the pH of a 0.014 M Ca(OH)₂ solution A) 1.85 B) 1.55 C) 12.15 D) 12.45 E) 15.85

Question

Quizplus · Accepted Answer

Calcium hydroxide, Ca(OH)2, is a strong base that dissociates completely in water to give calcium ions and hydroxide ions:

Ca(OH)2 → Ca2+ + 2 OH-

Therefore, the concentration of hydroxide ions in a 0.014 M Ca(OH)2 solution is:

[OH-] = 2 × [Ca(OH)2] = 2 × 0.014 = 0.028 M

Then, we can use the expression for the ion product constant of water to find the pH:

Kw = [H+][OH-] = 1.0 × 10^-14

pH = -log[H+]

pOH = -log[OH-] = -log(0.028) = 1.55

pH = 14 - pOH = 14 - 1.55 = 12.45

Therefore, the pH of a 0.014 M Ca(OH)2 solution is 12.45, and the correct answer is D.

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