For the reaction H₂O₂(g) $\rarr$ H₂O(g) + ¹/₂O₂(g), $\Delta$H^$\circ$ = -106 kJ/mol and $\Delta$S^$\circ$ = 58 J/K·mol at 25^$\circ$C. Calculate $\Delta$G^$\circ$ for this reaction at this temperature. A) -423 kJ/mol B) -323 kJ/mol C) -223 kJ/mol D) -123 kJ/mol E) None of the above

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The Answer of For the reaction H₂O₂(g) $\rarr$ H₂O(g) + ¹/₂O₂(g), $\Delta$H^$\circ$ = -106 kJ/mol and $\Delta$S^$\circ$ = 58 J/K·mol at 25^$\circ$C. Calculate $\Delta$G^$\circ$ for this reaction at this temperature. A) -423 kJ/mol B) -323 kJ/mol C) -223 kJ/mol D) -123 kJ/mol E) None of the above

For the Reaction H2O2(g) →\rarr→ H2O(g) + 1/2O2(g) Δ\DeltaΔ H ∘\circ∘ = -106 KJ/mol And

For the Reaction H₂O₂(g) $\rarr$ H₂O(g) + ¹/₂O₂(g) $\Delta$ H^$\circ$ = -106 KJ/mol And