Predict the signs (-, +, or 0) of $\Delta$H and $\Delta$S, in that order, for the process: H₂O(l) $\rarr$H₂O(s). A) 0, - B) 0, + C) +, + D) -, - E) None of the above

Question

Quizplus · Accepted Answer

For the process H2O(l) → H2O(s), the enthalpy change (ΔH) is negative because it releases heat (exothermic process), and the entropy change (ΔS) is negative because the system goes from a more disordered state (liquid) to a more ordered state (solid).

Predict the Signs (-, +, or 0) Of Δ\DeltaΔ H And Δ\DeltaΔ

Predict the Signs (-, +, or 0) Of $\Delta$ H And $\Delta$