Which of the following choices constitutes a simultaneous solution to these equations? $$\begin{array} { l }
3 x + 2 y = 6 \
6 x + 3 y = 12
\end{array}$$
A) x = 1, y = 1.5
B) x = .5, y = 2
C) x = 0, y = 3
D) x = 2, y = 0
E) x = 0, y = 0

Question

Which of the following choices constitutes a simultaneous solution to these equations? $$\begin{array} { l } 
3 x + 2 y = 6 \
6 x + 3 y = 12
\end{array}$$
A) x = 1, y = 1.5
B) x = .5, y = 2
C) x = 0, y = 3
D) x = 2, y = 0
E) x = 0, y = 0

Quizplus · Accepted Answer

To solve the system, we can multiply the first equation by 2 to get $6x+4y=12$. 
Now we have the system of equations:
\begin{align*}
6x+3y&=12 \
6x+4y&=12 \
\end{align*}
Subtracting the first equation from the second gives $y=0$, and substituting this into either equation gives $x=2$. Thus, the only simultaneous solution is $\boxed{	extbf{(D) } x=2, y=0}$.

Which of the Following Choices Constitutes a Simultaneous Solution to These