Employees of a local university have been classified according to gender and job type. $ \quad$$ \quad$$ \quad$$ \quad$$ \quad$$ \quad$$ \quad$$ \quad$$ \quad$$ \quad$$ \quad$$ \quad$$ \quad$$\text { Gender }$

$\begin{array} { l c c }
\text { Job } & \text { Male (M) } & \text { Female (F) } \
\text { Faculty (FA) } & 110 & 10 \
\text { Salaried staff (SS) } & 30 & 50 \
\text { Hourly staff (HS) } & 60 & 40
\end{array}$
If an employee is selected at random,what is the probability that the employee is female or works as a member of the faculty?
A)0.73
B)0.08
C)0.33
D)0.70
E)0.05

Question

Employees of a local university have been classified according to gender and job type. $ \quad$$ \quad$$ \quad$$ \quad$$ \quad$$ \quad$$ \quad$$ \quad$$ \quad$$ \quad$$ \quad$$ \quad$$ \quad$$\text { Gender }$

$\begin{array} { l c c } 
\text { Job } & \text { Male (M) } & \text { Female (F) } \
\text { Faculty (FA) } & 110 & 10 \
\text { Salaried staff (SS) } & 30 & 50 \
\text { Hourly staff (HS) } & 60 & 40
\end{array}$
If an employee is selected at random,what is the probability that the employee is female or works as a member of the faculty?
A)0.73
B)0.08
C)0.33
D)0.70
E)0.05

Quizplus · Accepted Answer

The probability of selecting a female is $ \frac{100}{300} = 0.33 $. The probability of selecting a faculty member is $ \frac{120}{300} = 0.40 $. The probability of selecting a female faculty member is $ \frac{10}{300} = 0.03 $. Using the formula for the probability of either event occurring: $ P(F \cup FA) = P(F) + P(FA) - P(F \cap FA) = 0.33 + 0.40 - 0.03 = 0.70 $.

Employees of a Local University Have Been Classified According to Gender