Container 1 has 8 items,3 of which are defective.Container 2 has 5 items,2 of which are defective.If one item is drawn from each container:
What is the probability that only one of the items is defective?
A)0.2250
B)0.3000
C)0.0250
D)0.4000
E)0.1500

Question

Quizplus · Accepted Answer

The probability that only one item is defective is the sum of the probabilities of drawing a defective item from one container and a non-defective item from the other. From Container 1, the probability of drawing a defective item is 3/8, and a non-defective item from Container 2 is 3/5. From Container 2, the probability of drawing a defective item is 2/5, and a non-defective item from Container 1 is 5/8. Thus, the total probability is (3/8 * 3/5) + (5/8 * 2/5) = 9/40 + 10/40 = 19/40 = 0.475. However, the closest option is 0.4000, which suggests a rounding or option error.

Container 1 Has 8 Items,3 of Which Are Defective