The number of ways to arrange x successes among n trials is equal to
A) $\frac { n ! } { x ! ( n - x ) ! }$
B) $\frac { n ! } { ( n - x ) ! }$
C) $n / x$
D) $n ! /x! $

Question

Quizplus · Accepted Answer

This formula is commonly known as the binomial coefficient and represents the number of ways to choose x items out of n items without replacement and without regard to order. It can also be written as $\binom{n}{x}$. The formula in choice A is the correct way to calculate this value.

The Number of Ways to Arrange X Successes Among N n!x!(n−x)!\frac { n ! } { x ! ( n - x ) ! }x!(n−x)!n!​

The Number of Ways to Arrange X Successes Among N $\frac { n ! } { x ! ( n - x ) ! }$