The pressure at a depth of 1.25 m in a tank of liquid is measured to be 125.5 kPa. The tank is open to the outside air, which is at a pressure of 102.0 kPa. What is the density of the fluid? A) 1,920 kg/m³ B) 10,200 kg/m³ C) 18,800 kg/m³ D) 2,400 kg/m³

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Quizplus · Accepted Answer

The pressure difference between the pressure at depth and the atmospheric pressure is due to the liquid column. This difference (125.5 kPa - 102.0 kPa = 23.5 kPa) is used to calculate the density of the fluid using the formula $ \rho = \frac{\Delta P}{gh} $, where $ \Delta P = 23.5 \times 10^3 \, \text{Pa} $, $ g = 9.81 \, \text{m/s}^2 $, and $ h = 1.25 \, \text{m} $. Solving gives $ \rho = \frac{23.5 \times 10^3}{9.81 \times 1.25} \approx 1,920 \, \text{kg/m}^3 $.

The Pressure at a Depth of 1