Mercury has a density of 13,600 kg/m³.The column of mercury that would produce a pressure of 1.0135 $\times$ 10⁵ N/m² is A) 32.120 in. B) 29.920 in. C) 25.430 in. D) 19.800 in. E) 9.8000 in.

Question

Quizplus · Accepted Answer

The pressure produced by a column of liquid can be calculated using the formula P = ρgh, where P is pressure, ρ is the density of the liquid, g is acceleration due to gravity, and h is the height of the column. Rearranging the formula to solve for h, we get h = P/ρg. Substituting the given values, we get h = (1.0135 x 10^5 N/m^2) / (13,600 kg/m^3 x 9.81 m/s^2) ≈ 29.92 meters. Converting meters to inches (1 meter = 39.37 inches), we get h ≈ 1181.1 inches ≈ 29.92 inches. Therefore, the column of mercury that would produce a pressure of 1.0135 x 10^5 N/m^2 is approximately 29.92 inches high, which is closest to choice B (29.920 in.).

Mercury Has a Density of 13,600 Kg/m3 ×\times× 105 N/m2 Is A) 32

Mercury Has a Density of 13,600 Kg/m³ $\times$ 10⁵ N/m² Is
A) 32