A 2.0 kg mass is connected to a spring with a spring constant of 9.0 N/m.The displacement is given by the expression x(t) = 12.0 cm sin($\omega$ t).What is the maximum displacement of the simple harmonic motion?
A) 8.0 cm
B) 12 cm
C) 20 cm
D) 24 cm
E) 30 cm

Question

Quizplus · Accepted Answer

The maximum displacement in simple harmonic motion is the amplitude of the motion, which is given directly in the expression x(t) = 12.0 cm sin(ωt). Therefore, the maximum displacement is 12 cm.

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