A rod with a diameter of 3.00 mm,projects 2.0 cm horizontally outward from a wall.A 50.0 N weight is hung from the end of the rod and the rod deflects downward by 2.00 $\times$ 10^-6 m.The shear strain of the rod is A) 1.00 $\times$ 10^-4. B) 1.50 $\times$ 10^-4. C) 2.00 $\times$ 10^-4. D) 2.50 $\times$ 10^-4. E) 3.00 $\times$ 10^-4.

Question

Quizplus · Accepted Answer

Shear strain is the deflection divided by the length of the rod. Here, shear strain = (2.00 * 10^-6 m) / (2.0 * 10^-2 m) = 1.00 * 10^-4.

A Rod with a Diameter of 3 ×\times× 10-6 M ×\times× 10-4 ×\times×

A Rod with a Diameter of 3 $\times$ 10^-6 M $\times$ 10^-4 $\times$